核心提示：遍历某个数组里的字段，拼接到需要的对象里,相对应的修改字段名称（代码实例）var aa = {people: [{id: 1,name: peng,lastName: yaping,email: 66...
遍历某个数组里的字段，拼接到需要的对象里,相对应的修改字段名称（代码实例）
var aa = {
"people": [
{
"id": 1,
"name": "peng",
"lastName": "yaping",
"email": "6666666@qq.com"
}
],
"values":[]
}
var bb = [
{"years":"2016","day":"aaa"},
{"years":"2017","day":"bbb"},
{"years":"2018","day":"ccc"},
]
//遍历数组 for循环
for(var i=0;i<bb.length;i++){
//console.log("for遍历数组",bb[i].years);
}
//遍历数组for in
for(var i in bb){
//console.log("for in遍历数组",bb[i]);
//数据结构根据后端的API文档
//这里的操作,有时需要的对象里面的字段名称要改变
var cc ={};
cc.enen = bb[i].years;
cc.chch = bb[i].day;
console.log(cc);
aa.values.push(cc);
}
console.log(aa);
